17. The age of father 10 years
ago was thrice the age of his son. Ten years hence, the father’s age will be
twice that of his son. The ratio of their present ages is:
A.5 : 2 B.7 : 3
C.9 : 2 D.13 : 4
Answer: 7 : 3
Explanation:
Let sons age 10 years ago = x.
Then, fathers age 10 years ago
= 3x.
2(x+ 10+ 10) = (3x + 10 + 10)so
x = 20.
Ratio of their present ages =
(3x + 10) : Cx + 10) 70: 30 = 7 :3.
