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1.
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Father
is aged three times more than his son Ronit. After 8 years, he would be two
and a half times of Ronit's age. After further 8 years, how many times would
he be of Ronit's age?
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Answer: Option A
Explanation:
Let Ronit's present age be x years.
Then, father's present age =(x + 3x) years = 4x years.
8x +
16 = 5x + 40
3x =
24
x =
8.
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Hence, required ratio =
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(4x + 16)
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=
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48
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= 2.
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(x + 16)
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24
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