6. Eighteen years ago, a father
was three times as old as his son. Now the father is only twice as old as his
son. Then the sum of the present ages of the son and the father is
A. 54. B.
72
C. 105 D.
108
Answer:
Let the present ages of Father
and Son be 2x years and x years respectively.
Then (2x-18)=3(x-18)
2x-18=3x-54
x=54-18
x=36.
Required sum = (2x+x)
=3x
=3x36
=108 years.
