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6.
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Nitin's
age was equal to square of some number last year and the following year it
would be cube of a number. If again Nitin's age has to be equal to the cube
of some number, then for how long he will have to wait?
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|
A.
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10 years
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B.
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38 years
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C.
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39 years
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D.
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64 years
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Answer: Option B
Explanation:
Clearly, we have to first find two numbers
whose difference is 2 and of which the smaller one is a perfect square and the bigger
one a perfect cube.
Such numbers are 25 and 27.
Thus, Nitin is now 26 years old. Since the
next perfect cube after 27 is 64,
so required time period = (64 - 26) years =
38 years.
