Calenders Q2

2. What was the day of the week on 28th May, 2006?

A.        Thursday    B.        Friday

C.        Saturday      D.        Sunday

Answer: Option D

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2)  6 odd days

Jan.  Feb.   March    April    May

(31 +  28  +  31   +   30   +   28 ) = 148 days

 148 days = (21 weeks + 1 day) = 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd day.

Given day is Sunday.