10. From a point P on a level ground, the
angle of elevation of the top tower is 30°. If the tower is 100 m high, the
distance of point P from the foot of the tower is:
A. 149 m
B. 156 m
C. 173
m D.
200 m
Answer:
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Let AB be the
tower.
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Then, <APB =30° and AB= 100 m
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AB/AP= tan30°
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= 1 / √3
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AB = (AB x √3)= 100√3 m.
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= (100 x 1.73) m = 173 m.
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Title :
Heights Q10
Description : 10. From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P...
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