5. An observer 1.6 m tall is 203 away from a
tower. The angle of elevation from his eye to the top of the tower is 30º. The
heights of the tower is:
A. 21.6 m B.
23.2 m
C. 24.72 m D.
None of these
Answer: Option A
Explanation:
Let AB be the observer and CD be the tower.
Draw BE 
CD.
Then, CE = AB = 1.6 m,
BE = AC = 203 m.
 DE =
|
203
|
m = 20 m.
|
|
3
|
CD = CE + DE = (1.6 + 20) m = 21.6 m.
Title :
Heights Q5
Description : 5. An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of th...
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