8.
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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
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Answer: Option A
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
Let E
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= event that the ball drawn is neither red nor green
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= event that the ball drawn is blue.
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n(E) = 7.
P(E) =
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n(E)
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=
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7
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=
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1
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.
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n(S)
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21
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3
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