46.
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A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
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49 m2
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50 m2
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53.5 m2
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55 m2
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Answer:
Answer: Option A
Explanation:
Area of the wet surface
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= [2(lb + bh + lh) - lb]
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= 2(bh + lh) + lb
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= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2
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= 49 m2.
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Title : Volume 46Q
Description : 46. A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is: A. 49 m 2 B...
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