Solutions
(1-5)
1. (2) Here the number of
samples in both the years 1986 and 1991 is 1048000
Difference
of Percentage:
=
(12.1+3+0.8) – (10 + 1.4 + 0.1)
=
15.9 – 11.5 = 4.4
:
Required Ans: =4.4% of 1048000
=
4.4x1048000/100 = 4612
2. (1) It is obvious from
table.
3. (5) The percentage of
low malnourished children shows no increase from the previous one.
4. (4) Req. no. of
children = 0.5% of 1071000
=0.5
x 1071000/100 = 5355
5. (2) Req. no. of
children = (7.8 + 0.9 + 0.1) % of 1161000
=
8.8 x 1161000/100 = 1,02,168
Solutions
(6-10)
6. (4) The increase rate was
maximum in 2002
7. (1) We look at the table
minutely and calculate the per centage for selective years
i.e.
in the year 1999 out of 192, 122 cases were of typhoid, in 2001 out of 144 , 98
cases were of typhoid.
Percentage
of typhoid in 1999 = 122 x 100 /192
=63.54%
Percentage
of typhoid in 2001 = 98 x 100/144 = 68%
8. (3) Req. number of cases = 86
x 27500000/100000 = 23650
9. (5) Req. rate = 192 – 122 =
70
10. (2) Avg. rate of hepatitis =
27 + 44 + 47 + 86 + 56 + 57 + 39 + 86/8
=
442/8
Avg.
rate of typhoid = 46 + 60 + 60 + 109 + 122 + 99 + 98 + 96/8
=
690/8
Req.
difference = 690 – 442/8 = 248/8 = 31
