16. Two students appeared at an examination. One of them secured 9
marks more than the other and his marks was 56% of the sum of their marks. The
marks obtained by them are
A. 39,
30 B.
41, 32
C. 42,
33 D.
43, 34
Answer:
Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
‹=› 25(x+9)
‹=› 14 (2x + 9)
‹=›3x = 99
‹=›x = 33.
SO, their marks are 42 and 33.
