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41.
|
A
shepherd has 1 million sheep at the beginning of Year 2000. The numbers grow
by x% (x > 0) during the year. A famine hits his village in the next year
and many of his sheep die. The sheep population decreases by y% during 2001
and at the beginning of 2002 the shepherd finds that he is left with 1
million sheep. Which of the following is correct?
|
|
A.
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x
> y
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B.
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y
> x
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C.
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x =
y
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D.
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Cannot
be determined
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Answer - (A)
Solution:
Let us assume the value of x to
be 10%.
Therefore, the number of sheep in the herd at the beginning of year 2001 (end
of 2000) will be 1 million + 10% of 1 million = 1.1 million
In 2001, the numbers decrease by y% and at the end of the year the number sheep
in the herd = 1 million.
i.e., 0.1 million sheep have died in 2001.
In terms of the percentage of the number of sheep alive at the beginning of
2001, it will be (0.1/1.1)*100 % = 9.09%.
From the above illustration it is clear that x
> y.
Title : Percentage Q41
Description : 41. A shepherd has 1 million sheep at the beginning of Year 2000. The numbers grow by x% (x > 0) during the year. ...
Rating : 5
