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59.
|
The
volume of the sphere Q is 3764% less than the volume of sphere P and the
volume of sphere R is 1927% less than that of sphere Q. By what % is the
surface area of sphere R less than the surface area of sphere P?
|
|
A.
|
77.77
%
|
|
B.
|
87.5
%
|
|
C.
|
75 %
|
|
D.
|
67.5
%
|
Answer – (C)
Solution:
Let the volume of sphere P be 64
parts.
Therefore volume of sphere Q =64−(3764)% of 64=64−37=27 parts.
The volume of R
=27−(1927)*27=27−19=8 parts.
Volume ratio:
=P:Q:R=64:27:8
Radius ratio:
=P:Q:R=4:3:2
The surface area will be 16:9:5
Surface area of R is less than the surface area of sphere P
16k−4k=12k
Now, 12k16k*100=75%
Thus surface area of sphere R is
less than the surface area of sphere P by 75
%
Title : Percentage Q59
Description : 59. The volume of the sphere Q is 3764% less than the volume of sphere P and the volume of sphere R is 1927% less tha...
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