31. Three unbiased coins are tossed.What is the probability of getting at least 2 heads?
A. 1/2 B. 1/4
C. 1/3 D. 1/8
Answer:
Here S= {TTT, TTH, THT, HTT, THH, HTH, HHt, HHH}.
Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.
P(E) = n(E) / n(S)
= 4/8.
‹=›1/2.