32. Two dice are thrown together. What is the probability that the sum of the numbers on the two faces is divisible by 4 or 6?
A. 5/18 B. 7/18
C. 9/18 D. 12/18
Answer:
Here, n(S) =(6×6)= 36.
Let E be the event that the sum of the numbers on the two faces is divisible by 4 or 6.Then
E= {(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),((5,3),(6,2),(6,6)}
Then, n(E) = 14.
= 16.
Therefore, P(E) = n(E)/n(S)
= 14 / 36
= 7 / 18.
