18. Two
vessels A and B contain spirit and water mixed in the ratio 5:2 and 7:6 respectively.
Find the ratio n which these mixture be mixed to obtain a new mixture in vessel
c containing spirit and water in the
ratio 8:5?
Solution: Let the
C.P of spirit be Re 1 per liter.
Spirit
in 1 liter mix of A = 5/7 liter.
C.P
of 1 liter mix in A =5/7.
Spirit
in 1 liter mix of B = 7/13 liter.
C.P
of 1 liter mix in B =7/13.
Spirit
in 1 liter mix of C = 8/13 liter.
C.P
of 1 liter mix in C =8/13.
C.P
of 1 liter mixture in A 5/7 C.P of 1
liter mixture
in
B 7/13
Mean Price 8/13
1/13 9/91
Therefore
required ratio = 1/13 : 9/91 = 7:9.
