19. A milk
vendor has 2 cans of milk .The first contains 5% water and the rest milk. The
second contains 50% water. How much milk should he mix from each of the
container so as to get 12 liters of milk such that the ratio of water to milk
is 3:5?
Solution: Let cost
of 1 liter milk be Re 1.
Milk
in 1 liter mixture in 1st can = 3/4 lit.
C.P
of 1 liter mixture in 1st can =Re 3/4
Milk
in 1 liter mixture in 2n d can = 1/2 lit.
C.P
of 1 liter mixture in 2n d can =Re 1/2
Milk
in 1 liter final mixture = 5/8 lit.
Mean
Price = Re 5/8.
C.P
of 1 lt mix in 1st Re3/4 C.P of 1 lt mix
in 2nd Re1/2
Mean Price 5/8
1/8 1/8
There
ratio of two mixtures =1/8 :1/8 = 1:1.
So,
quantity of mixture taken from each can=1/2*12
= 6 liters.
